How do you find the amplitude and period of #y= -csc (5(x-pi))#?

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Answer 1 · 2018-07-14T13:02:05

As below.

Standard form of the cosecant function is

#A csc (Bx - C) + D#

#y = - csc (5x - 5pi)#

#A = -1, B = 5, C = 5 pi, D = 0#

Amplitude #= |A| = # NONE for cosecant function.

Period #= (2pi) / |B| = (2pi)/5#

Phase Shift # = -C / B = -(5pi)/5 = -5 pi#, #color(red)(5pi)# to the LEFT

Vertical Shift # = D = 0#