How do you find the amplitude and period of #y=csc(1/2theta)#?

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How do you find the amplitude and period of #y=csc(1/2theta)#?

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Answer 1 · 2018-04-25T12:42:58

The raw trig functions such as #csc theta# have period #2pi#, so #csc(theta/2)# will have period twice that, #4 pi#. The reciprocal functions like cosecant diverge twice per period, so their amplitudes are undefined.

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How do you find the amplitude and period of #y=csc(1/2theta)#?

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