How do you find the amplitude and period of #y=5csc3theta#? Trigonometry Graphing Trigonometric Functions Amplitude, Period and Frequency 1 Answer Kalyanam S. Jun 1, 2018 #Amplitude = |A| = 5# Period #= (2pi)/|B| = (2pi) / 3# Explanation: #y = A csc(Bx - C) + D# #y = 5 csc 3theta# # A = 5, B = 3# #Amplitude = |A| = 5# Period #= (2pi)/|B| = (2pi) / 3# Phase Shift # = - C / B = 0# Vertical Shift # = D = 0# Answer link Related questions How do you find the period and frequency of a sine function? How does amplitude relate to the unit circle? How do you calculate the period and frequency? How can amplitude be negative? How do the frequency and period relate to each other? How do you find the amplitude of a cosine function? What is the amplitude of the function #y=-3sin x#? What is the amplitude for the function #y=6sinx#? How do you find the amplitude and period of the function? Do period and frequency depend on amplitude? See all questions in Amplitude, Period and Frequency Impact of this question 1289 views around the world You can reuse this answer Creative Commons License