How do you find the amplitude and period of #y=5csc3theta#?

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Answer 1 · 2018-06-01T03:03:00

#Amplitude = |A| = 5#

Period #= (2pi)/|B| = (2pi) / 3#

#y = A csc(Bx - C) + D#

#y = 5 csc 3theta#

# A = 5, B = 3#

#Amplitude = |A| = 5#

Period #= (2pi)/|B| = (2pi) / 3#

Phase Shift # = - C / B = 0#

Vertical Shift # = D = 0#