How do you find the amplitude and period of #y=4sintheta#?

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Answer 1 · 2017-01-01T23:14:18

The amplitude is #4# and the period is #2pi#.

Find the amplitude and period of #y=color(red)4sintheta#.

A sine function can be written as #y=Asin(Bx-C)+D#

where #A# is the amplitude

#(2pi)/B# is the period

#C/B# is the phase shift and

#D# is the vertical shift.

This example, #y=4sintheta#, may be be written as
#y=color(red)4sincolor(blue)1theta# where
#A=color(red)4# and #B=color(blue)1#

The amplitude is #color(red)4# and the period is #(2pi)/color(blue)1=2pi#.