How do you find the amplitude and period of #y=4cos(3/4theta)#?

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Answer 1 · 2018-05-31T15:43:39

As below

Standard form of the cosine function is

#y = A cos (Bx - C) + D#

Given : #y = 4 cos ((3/4)theta)#

#Amplitude = |A| = 4#

Period #= (2pi)/|B| = (2pi)/(3/4) = (8pi)/3#

Phase Shift # = -C / B = 0#, no Shift

Vertical Shift # = D = 0#, no Shift