How do you find the amplitude and period of #y=-3cos(2t)#?

1 Answer
Jim G.
Jan 28, 2017

#"amplitude "=3," period "=pi#

Explanation:

The standard form of the #color(blue)"cosine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b" and vertical shift "=d#

#"here " a=-3,b=2,c=0,d=0#

#rArr"amplitude "=|-3|=3" and period "=(2pi)/2=pi#

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