How do you find the amplitude and period of a function y = -½ cos(π/3) x?

1 Answer
Aug 5, 2018

color(brown)("Amplitude " = 1/2, "Period " = 6

Explanation:

Standard form of a cosine function is y = A cos(Bx - C) + D

y = -1/2 cos(pi/3 x)

A = -1/2, B = pi/3, C = D = 0

Amplitude = |A| = |-1/2| = 1/2

"Period " = (2pi) / |B| = (2pi) / (pi/3) = 6

"Phase Shift " = -C / B = 0#

"Vertical Shift ' = D = 0

graph{-1/2 cos(pi/3 x) [-10, 10, -5, 5]}