How do you find the 4th term in the expansion of #(4y+x)^4#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer Ratnaker Mehta · Jumbotron Aug 4, 2016 #16yx^3#. Explanation: The #(r+1)^(th)# term #T_(r+1)#, in the expansion of #(a+b)^n# is, #T_(r+1)=""^nC_r*a^(n-r)*b^r# So, in our case, for the read. #4^(th)# term, #T_4# we have, #r=3, n=4, a=4y, and, b=x# #:. T_4=""^4C_3*(4y)^(4-3)*x^3# #T_4=4*4y*x^3=16yx^3# Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 10755 views around the world You can reuse this answer Creative Commons License