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How do you find the 1st and 2nd derivative of #2e^(2x)#?

1 Answer

Oct 7, 2016

Using #d/dx e^(mx)=me^x#

Explanation:

so #d/dx 2e^(2x)=2d/dx e^(2x)=2(2e^(2x))=4e^(2x)#
And so, The #d^2/dx^2 2e^(2x)=d/dx 4e^(2x)=4(2e^(2x))=8e^(2x)#

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