How do you find tan alpha = -15/8, with alpha in quadrant II?

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How do you find tan alpha = -15/8, with alpha in quadrant II?

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Answer 1 · 2016-06-13T11:26:08

#tan(alpha)= -15/8# when #alpha= 118.07^0#

Explanation:

#tan^-1(15/8)=tan^-1(1.875) =61.93^0#; #alpha# is in a second quadrant and tan is negative there. So #tan(180-alpha)= -15/8 :.alpha= 180-61.93 =118.07^0#[Ans]

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How do you find tan alpha = -15/8, with alpha in quadrant II?

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