How do you find sin(x) and cos(x) if $tan(x)=sqrt(3)$ ?

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How do you find sin(x) and cos(x) if $tan(x)=sqrt(3)$ ?

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Answer 1 · 2015-04-15T15:48:41

Sin x = $sqrt3/2$ ; cos x = $1/2$

Make a Right triangle and for one of the acute angles 'x' mark its base leg as 1 and the opposite leg $sqrt3$ . Use Pythagoras theorem to find the hypotenuse of the right triangle. That would come out to be 2. Now sin x would be $sqrt3/2$ and cos x would be $1/2$

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How do you find sin(x) and cos(x) if $tan(x)=sqrt(3)$ ?

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How do you find sin(x) and cos(x) if $tan(x)=sqrt(3)$ ?