How do you find nth term rule for 1,-6,36,-216,...?
1 Answer
Aug 23, 2017
Explanation:
"these represent the terms in a geometric sequence."
a,ar,ar^2,ar^3,......,ar^(n-1)
"where a represents the first term and r the common ratio"
r=a_2/a_1=a_3/a_2=....=a_n/a_(n-1)
"here "r=(-6)/1=36/(-6)=(-216)/36=-6
"the nth term is calculated using "
•color(white)(x)a_n=ar^(n-1)=1xx(-6)^(n-1)=(-6)^(n-1)
