How do you find intercepts, extrema, points of inflections, asymptotes and graph g(x)=x+32/x^2?

1 Answer
Dec 1, 2017

Please see below for a partial solution.

Explanation:

g(x) = x+32/x^2

x intercepts
g(x) = 0 at x=-32/x^2
which happens at x^3 = -32

so x = root(3)(-32) = -2root(3)4

y intercept
None. g(0) does not exist.

Asymptotes

lim_(xrarr0)g(x) = oo, so x=0 (the y-axis) is a verticle asymptote..

lim_(xrarr00)g(x) = oo so there is no horizontal asymptote.

lim_(xrarroo)(g(x)-x) = 0 so y=x is an oblique (slant) asymptote)

Analysis of first derivative

g'(x) = 1-64/x^3 = (x^3-64)/x^3 is undefined at x=0 and is 0 at x=4.

On (-oo,0), we have g'(x) > 0 so g is increasing.
x=0 is not a critical number.

On (0,4), we have g'(x) < 0 so g is decreasing.
On (4,oo), we have g'(x) > 0 so g is increasing.

f(4)=6 is a local minimum.