How do you graph F(x,y)=sqrt(x^2+y^2-1)+ln(4-x^2-y^2)?
1 Answer
Mar 26, 2015
Hello,
-
Let
Sigma the surface of your functionF : it's a surface of revolution becauseF(x,y) = f(r) wherer = sqrt(x^2+y^2) . Precisely,f(r) = sqrt(r^2-1) + ln(4-r^2) -
First, plot the curve of
f : r \mapsto sqrt(r^2 -1) + ln(4-r^2) . You get
- Now, turn this curve around
z -axes in 3D-space. You get the surfaceSigma
