How do you find equation of line through point (5, -2) parallel to line 3y+7=-8?

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Answer 1 · 2016-06-09T15:49:21

#y=-2#

Subtract #color(blue)(7)# from both sides

#color(brown)(3y+7=-8" "->" "3y+7color(blue)(-7)=-8color(blue)(-7))#

#3y=-15#

Divide both sides by 3

#3/3 y=-15/3#

#1xxy=-5#

#y=-5" "larr" Parallel to the x-axis"#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#y=-2# is parallel to the other equation and passes through the point (5,-2).

Tony B