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How do you find #csc x= 2#?

1 Answer

Jun 24, 2018

#x=pi/6+2npi# and #x=(5pi)/6+2npi# where n is an integer

Explanation:

#cscx=2#

#1/sinx=2#

#sinx=1/2#

#x=pi/6,pi-pi/6,...#

In general form,

#x=pi/6+2npi# and #x=(5pi)/6+2npi# where n is an integer

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