How do you find an equation of the tangent line to the graph of the function #f(x) = (sqrtx)*(2-x)^2# at (1/2, 3/2)? Calculus Derivatives Tangent Line to a Curve 1 Answer Jim H May 6, 2015 The point #(1/2, 3/2)# is not on the graph of that function. #f(1/2) = 1/sqrt2 (3/2)^2 != 3/2# Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve #y=x^3-9x# at the point where #x=1#? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve #3y^2-2x^2=1#? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 1270 views around the world You can reuse this answer Creative Commons License