# How do you find an equation of a line containing the point (3, 2), and perpendicular to the line y - 2 = (2/3)x?

##### 1 Answer

May 21, 2016

#y=-3/2 x+13/2#

#### Explanation:

Given -

#y-2=2/3 x#

Rewrite it -

#y=2/3 x+2#

Its Slope

Two lines are perpendicular if -

#m_1 xx m_2 = -1#

Find the slope of the perpendicular line

#2/3 xx m_2= -1#

#m_2= -1 xx 3/2=-3/2#

The perpendicular line is passing through the point

Its equation is -

#y-y_1=m2(x-x_1)#

#y-2=-3/2(x-3)#

#y=-3/2x+9/2+2#

#y=-3/2 x+13/2#