How do you find all values of x in the interval [0, 2pi] in the equation $Sin 2pix=0$ ?

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Answer 1 · 2016-04-17T20:50:45

$S={0, 1/2,1,3/2,2,....,360}$

$2pix=sin^-1 0$

$2pix=pin$

$x=1/2 n$

$n=0, x=0$

$n=1,x=1/2$

$n=2, x=1$

$n=3, 3/2$
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$n=720, x=360$

$S={0, 1/2,1,3/2,2,....,360}$

How do you find all values of x in the interval [0, 2pi] in the equation Sin 2pix=0Sin 2pix=0?