How do you find all values of x in the interval [0, 2pi] in the equation # (cos x+1) (2cos^2 x-3 cos x-2) =0#?
1 Answer
Mar 15, 2016
Explanation:
Solve the 2 factors:
a. (cos x + 1) = 0 --> cos x = -1 -->
b.
Use the improved quadratic formula to solve for cos x.
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