How do you find all values of x in the interval [0, 2pi] in the equation #2 cos x - 1=0#?

Related questions

• How do you find all solutions trigonometric equations?
• How do you express trigonometric expressions in simplest form?
• How do you solve trigonometric equations by factoring?
• How do you solve trigonometric equations by the quadratic formula?
• How do you use the fundamental identities to solve trigonometric equations?
• What are other methods for solving equations that can be adapted to solving trigonometric equations?
• How do you solve #\sin^2 x - 2 \sin x - 3 = 0# over the interval #[0,2pi]#?
• How do you find all the solutions for #2 \sin^2 \frac{x}{4}-3 \cos \frac{x}{4} = 0# over the...
• How do you solve #\cos^2 x = \frac{1}{16} # over the interval #[0,2pi]#?
• How do you solve for x in #3sin2x=cos2x# for the interval #0 ≤ x < 2π#