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How do you find all the real and complex roots of #x(x^2 - 4)(x^2 + 16) = 0#?

1 Answer

Mar 5, 2016

#x=0,+-2,+-4i#

Explanation:

#x(x^2-4)(x^2+16)=0#
#x(x+2)(x-2)(x+4i)(x-4i)=0#
#:.##x=0,+-2,+-4i#

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