How do you find all the real and complex roots of #x^2-4=0#? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Jim G. Aug 2, 2018 #x=+-2# Explanation: #"add 4 to both sides"# #x^2=4rArrx=+-2# Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 1227 views around the world You can reuse this answer Creative Commons License