How do you find all the real and complex roots of #P(z)=z^4+1#? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Konstantinos Michailidis Feb 27, 2016 The roots of #P(z)=z^4+1# are #z^4+1=0=>z^4=-1=>z^4=e^(2pi*i+2kpi*i)=> z=e^(pi*i/4*(1+2k))# for #k=0,1,2,3# So finally the roots are #z=\pm\frac{1+i}{\sqrt 2},\ \ z=\pm\frac{1-i}{\sqrt 2}# Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 1328 views around the world You can reuse this answer Creative Commons License