How do you find all real number solutions to root3(6y+2)-2=0?
1 Answer
Nov 16, 2016
Explanation:
your equation
- add 2 to both sides
root3(6y+2)=2 - cube both sides to get rid of cube-root
6y+2=2^3 - simplify the cube
6y+2=8 - subtract 2 from both sides
6y=8-2 - simplify
6y=6 - divide both sides by 6 to isolate
y on left side
y=6
