How do you find all real number solutions to $root3(2x+3)-1=0$ ?

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Answer 1 · 2016-11-13T22:59:33

$root(3)(2x+ 3) = 1$

$(2x + 3)^(1/3) = 1$

$((2x+ 3)^(1/3))^3 = 1^3$

$2x + 3 = 1$

$2x = -2$

$x = -1$

Hopefully this helps!

How do you find all real number solutions to root3(2x+3)-1=0root3(2x+3)-1=0?