How do you find all points on the y-axis system coordinate system that are 5 units from Cartesian the point (4,0)?

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Answer 1 · 2017-01-14T16:27:00

The Reqd. pts. are $(0,3),and,(0,-3).$

Let the reqd. pt. be $P(x,y)," and, the given pt. be "Q(4,0)$ .

$P(x,y) in Y"-Axix "rArr x=0 rArr P(x,y)=P(0,y)$

Next, $PQ=5 rArr PQ^2=5^2$ .

$(0-4)^2+(y-0)^2=5^2 [because," the Distance Formula]"$ .

$rArr y^2=5^2-4^2=3^2$ .

$rArr y=+-3$

Hence, the Reqd. pts. are $(0,3),and,(0,-3)$