How do you find a_9 when a_1 = 1000, r = 1/3?
1 Answer
May 25, 2016
Explanation:
For the standard geometric sequence.
a,ar,ar^2,ar^3,..............,ar^(n-1)
where a is 1st term
r ,the common ratio
=a_2/a_1=a_3/a_2=....=a_n/a_(n-1) and the nth term
a_n=ar^(n-1) here n = 9 , a = 1000 and
r=1/3
rArra_9=1000(1/3)^8=1000/3^8=1000/6561