How do you find a vehicle's velocity and acceleration in 1 second if an automobile's velocity starting from rest is $v(t)= 90/4t+10$ where v is measured in feet per second?

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Answer 1 · 2015-02-07T18:21:20

$v=32.5ft//s$
$a=32.5ft//s//s$

$v=(90t)/4+10$

If $t=1$ $v=(90xx1)/4+10=32.5ft//s$

Acceleration = change in velocity per second. The automobile goes from zero to 32ft/s in 1 second so the acceleration $a=32ft//s//s$

You don't need calculus for that. Just common sense.

How do you find a vehicle's velocity and acceleration in 1 second if an automobile's velocity starting from rest is v(t)= 90/4t+10v(t)= 90/4t+10 where v is measured in feet per second?