How do you factorize $20p + 15pq - 60q^2-80q$ completely?

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Answer 1 · 2017-12-02T18:23:56

$5(4+3q)(p-4q)$

$= 20p-80q+q(15p-60q)$
$= 20(p-4q) + 15q(p-4q)$
$= (20+15q)(p-4q)$
$= 5(4+3q)(p-4q)$

How do you factorize 20p + 15pq - 60q^2-80q20p + 15pq - 60q^2-80q completely?