How do you factor $y = 2 x^{3} + 16 x 2 + 7 x + 56$ $y= 2x^3 + 16x2 + 7x + 56$ ?

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Answer 1 · 2015-12-30T13:15:23

Use factor by grouping. The working is shown below.

$y = 2 x^{3} + 16 x^{2} + 7 x + 56$ $y=2x^3+16x^2 + 7x + 56$

$y = (2 x^{3} + 16 x^{2}) + (7 x + 56)$ $y=(2x^3+16x^2)+(7x+56)$ Grouped the terms.

Next step is to factor out the GCF from each group.

$y = 2 x^{2} (x + 8) + 7 (x + 8)$ $y=2x^2(x+8)+7(x+8)$

Now to factor out GCF of both the groups.

$y = (x + 8) (2 x^{2} + 7)$ $y=(x+8)(2x^2+7)$

This is the final answer as we can't factor it further.

How do you factor y=2x3+16x2+7x+56y= 2x^3 + 16x2 + 7x + 56 ?