How do you factor $x^3 + 4x^2 - 9x - 6 =0$ ?

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Answer 1 · 2015-11-26T00:17:09

$(x+2)(x+3)(x-3)(2x^2-3)=0$

Whenever you have a polynomial with more than $3$ terms, it is always a good idea to group your like terms together:

$x^3+4x^2-9x-6=0$
$x^3-9x+4x^2-6=0$
$x(x^2-9)+2(2x^2-3)=0$
$x(x+3)(x-3)+2(2x^2-3)=0$
$(x+2)(x+3)(x-3)(2x^2-3)=0$

How do you factor x^3 + 4x^2 - 9x - 6 =0x^3 + 4x^2 - 9x - 6 =0?