How do you factor $x^3 + (2)x^2 + (4)x + 8$ ?

Question

1531 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-05T16:36:57

$x^3+2x^2+4x+8=(x+2)(x^2+4)=(x+2)(x+2i)(x-2i)$

The solution to a cubic is not simple. This one has an 'obvious' factor.Rewrite the equation $x^3+4x +2x^2+8=x(x^2+4)+2(x^2+4)=(x+2)(x^2+4)$

How do you factor x^3 + (2)x^2 + (4)x + 8x^3 + (2)x^2 + (4)x + 8?