How do you factor $x^2y-16y+32-2x^2$ ?

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Answer 1 · 2015-05-11T06:27:13

Putting the polynomial in descending order first helps:

$x^2y-16y+32-2x^2 = x^2y-2x^2-16y+32$

$=(x^2y-2x^2)-(16y-32)$

$=x^2(y-2)-16(y-2)$

$=(x-16)(y-2)$

How do you factor x^2y-16y+32-2x^2x^2y-16y+32-2x^2?