How do you factor x^2-81? Algebra Polynomials and Factoring Factoring Completely 1 Answer Alan P. May 18, 2016 x^2-81=color(green)((x-9)(x+9)) Explanation: For the general case: color(white)("XXX")(x^2-a^2)=(x-a)(x+a) (x^2-81 ) = (x^2-9^2) substituting 9 for a in the general case gives: color(white)("XXX")(x-9)(x+9) Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-8? Which method do you use to factor 3x(x-1)+4(x-1) ? What are the factors of 12x^3+12x^2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-75 completely? How do you factor x^6-26x^3-27? How do you factor 100x^2+180x+81? See all questions in Factoring Completely Impact of this question 15425 views around the world You can reuse this answer Creative Commons License