How do you factor x2+3x5x215?

1 Answer
May 19, 2015

Please check the question?

y=4x2+3x15.

This trinomial can't be factored because D = b^2 - 4ac < 0.

The correct question should be: factor y=x3+3x5x215.
To factor, group the first term and the second term together:

y=x(x2+3)5(x2+3)=(x2+3)(x5)

Check by developing:y=x35x2+3x15. OK