How do you factor the polynomials hj2h+5j10?

1 Answer
May 15, 2017

(j2)(h+5)

Explanation:

group the terms as follows

hj2h+5j10

take out a common factor of h and 5 from the groups

h(j2)+5(j2)

the factor (j2) is common to both terms and can be
taken out as a common factor

(j2)(h+5)