How do you factor the polynomials #hj-2h+5j-10#?

1 Answer
May 15, 2017

#(j-2)(h+5)#

Explanation:

#"group the terms as follows"#

#color(blue)(hj-2h)color(red)(+5j-10)#

#"take out a common factor of h and 5 from the groups"#

#rArrh(j-2)+5(j-2)#

#"the factor " (j-2)" is common to both terms and can be "#
#"taken out as a common factor"#

#rArr(j-2)(h+5)#