How do you factor the polynomials $24ty-18t+4y-3$ ?

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Answer 1 · 2016-11-20T19:12:15

$24ty-18t+4y-3 = (6t+1)(4y-3)$

This polynomial factors by grouping:

$24ty-18t+4y-3 = (24ty-18t)+(4y-3)$

$color(white)(24ty-18t+4y-3) = 6t(4y-3)+1(4y-3)$

$color(white)(24ty-18t+4y-3) = (6t+1)(4y-3)$

How do you factor the polynomials 24ty-18t+4y-324ty-18t+4y-3?