How do you factor the polynomials $16 g h + 24 g - 2 h - 3$ $16gh+24g-2h-3$ ?

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How do you factor the polynomials $16 g h + 24 g - 2 h - 3$ $16gh+24g-2h-3$ ?

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Answer 1 · 2016-11-20T19:14:45

$16 g h + 24 g - 2 h - 3 = (8 g - 1) (2 h + 3)$ $16gh+24g-2h-3 = (8g-1)(2h+3)$

Explanation:

This polynomial factors by grouping:

$16 g h + 24 g - 2 h - 3 = (16 g h + 24 g) - (2 h + 3)$ $16gh+24g-2h-3 = (16gh+24g)-(2h+3)$

$16 g h + 24 g - 2 h - 3 = 8 g (2 h + 3) - 1 (2 h + 3)$ $color(white)(16gh+24g-2h-3) = 8g(2h+3)-1(2h+3)$

$16 g h + 24 g - 2 h - 3 = (8 g - 1) (2 h + 3)$ $color(white)(16gh+24g-2h-3) = (8g-1)(2h+3)$

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How do you factor the polynomials $16 g h + 24 g - 2 h - 3$ $16gh+24g-2h-3$ ?

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How do you factor the polynomials $16 g h + 24 g - 2 h - 3$ $16gh+24g-2h-3$ ?