How do you factor the expression #7(x-y)-z(x-y)#?

1 Answer
EZ as pi
Jul 23, 2016

#(x-y)(7-z)#

Explanation:

This is exactly the same as factoring #7a - za# where there is a common factor of #a#, leading to #a(7 - z)#

However, in this case, instead of a single variable as the common factor, there is an entire bracket which appears in both terms.

#7color(blue)((x-y))-zcolor(blue)((x-y))#

Divide each term by the common bracket

#color(blue)((x-y))(7-z)#

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