How do you factor #(pi)r^2 - 4(pi)r+4(pi) #?

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Answer 1 · 2016-10-02T18:40:13

=#pir^2#

Before you factor, you will see that there are two terms which are additive inverses. We end up with one term!

#pi r^2 -4pir +4pir#

=#pir^2#

If you factor anyway - take out a common factor of #pir#

=#pir(r +4-4)#

=#pir(r)#

=#pir^2#