How do you factor completely #x^(2/3)+5x^(1/3)-36#? Algebra Polynomials and Factoring Factoring Completely 1 Answer GiĆ³ · Alan P. Apr 19, 2016 I got: #(root3(x)+9)(root3(x)-4)# Explanation: We can try writing the fractional exponent as a root: #root3(x^2)+5root3(x)-36# set #root3(x)=s# we get: #s^2+5s-36=(s+9)(s-4)# or: #(root3(x)+9)(root3(x)-4)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 962 views around the world You can reuse this answer Creative Commons License