How do you factor completely $6 x^{2} + 18 x y + 12 y^{2}$ $6x^2 + 18xy + 12y^2$ ?

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Answer 1 · 2016-06-21T20:12:16

$6 (x + 2 y) (x + y)$ $6(x + 2y)(x + y)$

Always look to see if there is a common factor first.
In this case you can divide out a factor of 6 from all the terms.

$6 (x^{2} + 3 x y + 2 y^{2})$ $6(x^2 + 3xy +2y^2)$

Now, the factors of 2 which add up to 3 are 2 and 1.
The signs are the same, they are both positive.
There will be an x and a y term in each bracket.

$6 (x + 2 y) (x + y)$ $6(x + 2y)(x + y)$

How do you factor completely 6x2+18xy+12y2 6x^2 + 18xy + 12y^2?