How do you factor completely #4x^2 - 12x + 8#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Alan P. Apr 6, 2016 #4(x-1)(x-2)# Explanation: Given #color(white)("XXX")4x^2-12x+8# Extract the constant factor of #4# #color(white)("XXX")=4(x^2-3x+2)# Since #(-1)+(-2)=(-3)# and #(-1)xx(-2)=2# #color(white)("XXX")=4(x-1)(x-2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 5368 views around the world You can reuse this answer Creative Commons License