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How do you factor completely $4x^2 - 12x + 8$ ?

1 Answer

Apr 6, 2016

$4(x-1)(x-2)$

Explanation:

Given
$color(white)("XXX")4x^2-12x+8$

Extract the constant factor of $4$
$color(white)("XXX")=4(x^2-3x+2)$

Since $(-1)+(-2)=(-3)$ and $(-1)xx(-2)=2$
$color(white)("XXX")=4(x-1)(x-2)$

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