How do you factor completely $27+8t^3$ ?

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Answer 1 · 2016-09-16T17:06:28

$27 + 8t^3 = (3+2t)(9-6t+4t^2)$

$27, 8 and t^3$ are all cubes. Once you recognise that fact, you can factorise this expression by the general rule for "Sum of cubes".

$x^3 +y^3 = (x+y)(x^2-xy+y^2)$

$27 + 8t^3 = (3+2t)(9-6t+4t^2)$

How do you factor completely 27+8t^327+8t^3?