How do you factor completely #25x^2– 144#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Meave60 · EZ as pi Apr 30, 2016 #(5x+12)(5x-12)# Explanation: #25x^2-144# is a difference of squares, #a^2-b^2#, where #a=5x# and #b=12#, #a^2-b^2=(a-b)(a+b)#. Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 6843 views around the world You can reuse this answer Creative Commons License
