How do you factor by grouping $y^{2} + 3 y - 2 y - 6$ $y^2 + 3y - 2y - 6$ ?

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Answer 1 · 2015-05-22T07:26:22

$y^{2} + 3 y - 2 y - 6$ $y^2 + 3y -2y -6$

We can make groups of two to factorise this expression:
$(y^{2} + 3 y) - (2 y + 6)$ $color(blue)((y^2+3y) - color(red)((2y + 6)$

$y$ $color(blue)(y$ is common to both the terms in the first group, and $2$ $color(red)(2$ is common to both the terms in the second group:

We can write the expression as :
$y (y + 3) - 2 (y + 3)$ $y(y + 3) - 2(y+3)$

$= (y + 3) (y - 2)$ $=color(green)((y+3)(y-2)$ , is the factorised form.

How do you factor by grouping y^2 + 3y - 2y - 6y2+3y−2y−6y^2 + 3y - 2y - 6?