How do you factor by grouping $x y + 6 x + 2 y + 12$ $xy+6x+2y+12$ ?

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Answer 1 · 2015-05-17T07:52:22

$x y + 6 x + 2 y + 12$ $xy + 6x + 2y + 12$

We factor this expression by making groups of 2 terms
$= (x y + 6 x) + (2 y + 12)$ $= (xy + 6x) + (2y +12)$

Now we take the common factors out from each group
$= x (y + 6) + 2 (y + 6)$ $= x( y + 6) + 2( y + 6)$

$(y + 6)$ $( y + 6)$ is a common factor to each of the terms now:

$= (y + 6) (x + 2)$ $= ( y + 6)(x + 2)$

$(y + 6) (x + 2)$ $color(green)( ( y + 6)(x + 2))$ is the Factorised form of $x y + 6 x + 2 y + 12$ $xy + 6x + 2y + 12$

How do you factor by grouping xy+6x+2y+12xy+6x+2y+12xy+6x+2y+12?