How do you factor by grouping #xy+4x-2y-8#?

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Answer 1 · 2015-04-15T12:02:43

Try collecting #y# between the first and third term and #4# between the second and the fourth:
#y(x-2)+4(x-2)=# now collect #(x-2)#;
#(x-2)(y+4)#