How do you factor by grouping $x^3 + (2)x^2 + (4)x + 8$ ?

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Answer 1 · 2015-04-28T18:31:05

In this way:

$x^3+2x^2+4x+8=x^2(x+2)+4(x+2)=(x+2)(x^2+4)$

and we can not proceed further because the factor $x^2+4$ can't be factored in $RR$ .

How do you factor by grouping x^3 + (2)x^2 + (4)x + 8x^3 + (2)x^2 + (4)x + 8?